ANSYS Simply Supported Beam With Point Load.

 

ANSYS Simply Supported Beam With Point Load.

A point load (P) is a force that is applied at one infinitesimal point at a specific distance from the beam's ends. Go back to the calculator. Distributed Uniform Load (q) A force exerted over a surface is referred to as a uniform distributed load (q), where q stands for force per unit length.

                                Let's suppose a 4-meter beam made of Structural Steel has a tensile yield strength of 250MPa as shown in figure 1 

This image has an empty alt attribute; its file name is Circular%20Bar%20Design%20discription.jpg

For the design, we use NX 12 software with the dimension of 200*200 mm with a length of 4 meters we export the file in .igs formate and then we import it into Ansys and use the SpaceClaim feature inside Ansys for further editing the geometry, we want to know the maximum bending stress and maximum deflection so for that we use the split feature to split the face to apply point load on it. By doing hand calculation we find that there is the maximum deflection is 5.15 mm with maximum stress developed of 73.8 MPa for verifying our result for practical implementation we use Ansys.

This image has an empty alt attribute; its file name is Circular%20Bar%20Design%20discription.gif

Figure 2 Face Splitting for a point load.

After the split we go to the next step i.e. model to create a mesh, program-controlled mesh we use two faces mesh command to resize the mesh size and we reduced it from 30 mm to 10 mm and we got very fine meshing with 414052 Nodes and 244045 Elements.

                                              Figure 3 Fine Meshing of Faces

On applying 1000 N point load vertically downward Numerical Analysis we got the result as follow:

  • Maximum Deflection: 4.9 mm

                              Figure 4 Directional Deformation

  • Maximum Stress: 75.6 MPa

                                    Figure 5 Maximum Bending Stress

Thus by both Numerically Calculated and Handon Calculation, we can conclude that our assumption and calculation are correct.

 

Comments

Popular Posts